(x+4)(x+2)=(x+3)(x+5)

[tex] {x}^{2} + 6x + 8 = {x}^{2} + 8x + 15 \\ {x}^{2} - {x}^{2} + 8x - 6x + 15 - 8 \\ 2x + 7 \\ 2x = - 7 \\ x = \frac{ - 7}{2} \\ x = - 3.5[/tex]