Tentukan persamaan garis yg melalui titik (2,5) dan(-1,3)

rumus = y-y1/y2-y1=x-x1/x2-x1
y-5/3-5=x-2/-1-2
y-5/-2=x-2/-3
kalikan silang
-3(y-5)=-2(x-2)
-3y+15=-2x+4
-3y=-2x+4-15
-3y=-2x-11 atau 2x-3y+11=0

m = (y2 - y1)/(x2 - x1)
= ( 3 - 5)/(-1 - 2)
= -2/-3 = 2/3

y - y2 = m (x - x2)
y - 3 = 2/3 (x + 1)
y - 3 = 2/3x + 2/3
3y - 9 = 2x + 2 (kedua ruas di kali 3)
3y = 2x + 2 + 9
3y = 2x + 11
2x - 3y + 11 = 0