Matematika

Pertanyaan

mohon jawabanya ya ,beserta caranya ,No 15-19
mohon jawabanya ya ,beserta caranya ,No 15-19

1 Jawaban

  • 15) f(x) = mx + n
    f(2) = 2m + n = 7
    f(-1) = - m + n = - 2
    ---------------------------(-)
    3m = 9
    m = 3
    subtitusi
    - m + n = - 2
    - 3 + n = - 2
    n = - 2 + 3
    n = 1
    f(x) = mx + n
    f(x) = 3x + 1
    f(2) = 3(2) + 1 = 6 + 1 = 7 ( C )

    16) A

    17) m = ( y2 - y1 ) / ( x2 - X1 )
    m = ( - 10 - 5 ) / ( - 2 - 1 )
    m = - 15 / - 3
    m = 5 ( D )

    18) 2x - 3y + 4 = 0
    - 3y = - 2x - 4
    m = -2/-3
    m = ⅔
    gradien sejajar m1 = m2 = ⅔
    pers garis
    y - y1 = m ( x - X1 )
    y + 5 = ⅔ ( x - 2 )
    y = ⅔ x - 4/3 - 5 ( dikali 3)
    3y = 2x - 4 - 15
    3y - 2x = - 19
    3y - 2x + 19 = 0
    - 2x + 3y + 19 = 0
    2x - 3y - 19 = 0

    19) 3x + 2y = 8
    x - y = 1 |×2
    maka
    3x + 2y = 8
    2x - 2y = 2
    ----------------(+)
    5x = 10
    x = 2
    subtitusi
    x - y = 1
    2 - y = 1
    - y = 1 - 2
    - y = - 1
    y = 1
    nilai 4x + 5y
    = 4(2) + 5(1)
    = 8 + 5
    = 13 ( A )