tentukan persamaan garis yg tegak lurus dgn garis 5x+7y-7=0 dan melalui titik 4,-3

m1 = -a/b
m1 = -5/7
m1 × m2 = -1
-5/7 × m2 = -1
m2 = -1/-5/7
m2 = -1 × -7/5
m2 = 7/5
y - y1 = m(x - x1)
y - (-3) = 7/5(x - 4)
y + 3 = 7/5(x - 4)
5(y + 3) = 7(x - 4)
5y + 15 = 7x - 28
5y - 7x = -28 - 15
5y - 7x = -43