bantu yg bisa logaritma [tex] ^{2} log(a^{2} - b^{2}) = \: ^{2}log(a - b) [/tex]
Matematika
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Pertanyaan
bantu yg bisa logaritma
[tex] ^{2} log(a^{2} - b^{2}) = \: ^{2}log(a - b) [/tex]
[tex] ^{2} log(a^{2} - b^{2}) = \: ^{2}log(a - b) [/tex]
1 Jawaban
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1. Jawaban atiz
[tex]( {a}^{2} - {b}^{2} ) = (a - b) \\ (a -b )( a+ b) = ( a-b )\\ ( a+ b) = \frac{( a-b )}{( a-b )} \\ ( a+ b) = 1 \\ a = 1 - b[/tex]