Tentukan persamaan garis melalui (4,3) dan (-2,2)

y-y1 x-x1
-------- = -------
y2-y1 x2-x1

y-3 x- 4
----- = -------
2-3 -2-4

y-3 x-4
----- = -----
-1 -6

-6(y-3) = -1(x-4)
-6y+18 = -x +4
x - 6y + 18 - 4 = 0
x - 6y + 14 = 0