1. Tentukan nilai = x 2log^2 2x - 8 2^log 2x+12 = 0

²log² 2x - 8 . ²log 2x + 12 = 0

Misal : ²log 2x = a

²log² 2x - 8 . ²log 2x + 12 = 0
a² - 8a + 12 = 0
(a - 2)(a - 6) = 0
a = 2 atau a = 6

Utk a = 2
²log 2x = 2
2x = 2^2 ---> x = 2

Utk a = 6
²log 2x = 6
2x = 2^6
x = 64/2 ---> x = 32

Nilai x yg memenuhi :
2 dan 32