Matematika

Pertanyaan

Tentukan himpunan penyelesaian dari
A.lx+2l=2
B.l3x+1l=4

2 Jawaban

  • a.) lx+2l=2
    ✐ x+2 = 2
    x = 2-2
    x = 0
    ✐ -(x+2) = 2
    -x-2 = 2
    -x = 2+2
    -x = 4
    x = -4

    HP = {0, -4}

    b.) |3x+1| = 4
    ✐ 3x + 1 = 4
    3x = 4-1
    3x = 3
    x = 1
    ✐ -(3x+1) = 4
    -3x-1 = 4
    -3x = 4+1
    -3x = 5
    x = - 5/3

    HP = {- 5/3 , 1 }
  • A. |x+2|=2
    -> x+2=2
    -> x=2-2=0
    -> ( -x+2)=2
    -> -x=2+2
    -> -x=4 -> x = -4 -> Hp={-4}

    B. |3x+1|=4
    -> 3x+1=4
    -> 3x=4-1
    -> -3x= 4+1 =5 -> x= -5/3 Hp={-5/3}

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