Soal! sebuah kerucut memiliki jari jari 5cm dan panjang garis pelukis 13cm volume kerucutnya adalah...... [tex]a.40\pi \: cm {}^{2} \\ b.60\pi \: cm {}^{2} \\

Kelas 8 Matematika
Bab Bangun Ruang

t = √(s² - r²)
t = √(13² - 5²)
t = √(169 - 25)
t = √144
t = 12 cm

Volume = 1/3 . π . r . r . t
Volume = 1/3 . π . 5 . 5 . 12
Volume = 100 π cm^3

Mapel : Matematika
Bab : BRSL

r = 5 cm
s = 13 cm

[tex]t = \sqrt{13 ^{2} - 5^{2} } [/tex]
[tex]t = \sqrt{169 - 25} [/tex]
[tex]t = \sqrt{144} [/tex]
[tex]t = 12cm[/tex]

V = 1/3 × phi × r^2 × t
V = 1/3 × phi × 5^2 × 12
V = 1/3 × phi × 300
V = 100 × phi
V = 100 Phi cm^3