jika 2log 3=a dan 3loh5=b 9log 100

[tex]9\log100=\dfrac{2\log9}{2\log100} \\ \\ 2\log9=2\log3^2 \\ 2\log9=2(2\log3) \\ 2\log9=2a \\ \\ 2\log100=2\log(25\times4) \\ 2\log100=2\log25+2\log4 \\ 2\log100=2\log5^2+2\log2^2 \\ 2\log100=2(2\log5)+2(2\log2) \\ 2\log100=2(2\log3\times3\log5)+2(1) \\ 2\log100=2(ab)+2 \\ \\ 9\log100=\dfrac{2\log9}{2\log100} \\ 9\log100=\dfrac{2a}{2ab+2} \\ \\ 9\log100=\dfrac{a}{ab+1}[/tex]