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Matematika
albertlim3
Pertanyaan
Susahhh klii tolonggg pleaseee
2 Jawaban
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1. Jawaban DikyRes
(x+1)log(x-6) - (1/x+1)log8 = (log²5 - log²2)/(log2,5)
(x+1)log(x-6) - (x+1)^-1log8 = [(log5+log2)(log5-log2)] / log(5/2)
(x+1)log(x-6) - (x+1)log8^-1 = [(log5+log2)(log5-log2)] / (log5-log2)
(x+1)log8(x-6) = log5+log2
(x+1)log8x-48 = log10
(x+1)log8x-48 = 1
(x+1)log8x-48 = (x+1)log(x+1)
8x-48 = x+1
7x = 49
x = 7 -