Tentukan himpunan penyelesaian persamaan 2√2sin (3x-60°)-1 =1 untuk 0° ≤ x ≤ 360° = Tolong bantuannya

[tex]2 \sqrt{2} \sin(3x - {60}^{0} ) - 1 = 1 \\ 2 \sqrt{2} \sin(3x - {60}^{0} ) = 2 \\ \sin(3x - {60}^{0} ) = \frac{1}{2} \sqrt{2} \\ \\ \sin(3x - {60}^{0} ) = \sin( {45}^{0} ) \\ 3x - {60}^{0} = {45}^{0} \\ 3x = {105}^{0} \\ x = {35}^{0} \\ \\ atau \\ \\ \sin(3x - {60}^{0} ) = \sin( {135}^{0} ) \\ 3x - {60}^{0} = {135}^{0 } \\ 3x = {195}^{0} \\ x = {65}^{0} [/tex]