Tolong di jawab kawan...soalnya mmtk peminatan tdk tuntas Tentukan Hp persamaan berikut : (x²-5x + 5)²×+³ = (ײ - 5× + 5)³×-²

[tex]f(x) ^{g(x)} = {f(x)}^{h(x)} [/tex]

1. g(x) = h(x)
2. f(x) = 1
3. f(x) = 0, syaratnya g(x)>0 dan h(x)>0
4. f(x) = -1, syaratnya g(x) dan h(x) keduanya harus ganjil / keduanya genap

[tex](x ^{2} - 5x + 5) ^{2x + 3} = (x ^{2} - 5x + 5) ^{3x - 2} \\ \\ 1. \: g(x) = h(x) \\ \: 2x + 3 = 3x - 2 \\ 2x - 3x = - 2 - 3 \\ - x = - 5 \\ x = 5 \\ \\ 2. \: f(x) = 1 \\ (x ^{2} - 5x + 5) = 1 \\ \: x ^{2} - 5x + 5 - 1 = 0 \\ \: x ^{2} - 5x + 4 = 0 \\ (x - 4)(x - 1) = 0 \\ x = 4 \: atau \: x =1 \\ \\ 3. \: f(x) = 0 \\ x ^{2} - 5x + 5 = 0 \\ \\ 4. \:f(x) = - 1 \: \\ x ^{2} - 5x + 5 = - 1 \\ x ^{2} - 5x + 5 + 1 = 0 \\ x ^{2} - 5x + 6 = 0 \\ (x - 2)(x - 3) = 0 \\ x = 2 \: atau \: x = 3 \\ x = 2 \\ g(x) = 2x + 3 = 2.2 + 3 = 7 \\ h(x) = 3x - 2 = 3.2 - 2 = 3 \\ x = 3 \\ g(x) = 2x + 3 = 2.3 + 3 = 9 \\ h(x) = 3x - 2 = 3.3 - 2 = 7[/tex]

HP = {1, 2, 3, 4, 5}
Semoga membantu..
Silahkan tanya kalo ada yg gk jelas :)