yang tau dong? beserta cara

∫ (8x³ - 12x² + 6x) dx
= (8/3+1)x³⁺¹ - (12/2+1)x²⁺¹ + (6/1+1)x¹⁺¹ + C
= (8/4)x⁴ - (12/3)x³ + (6/2)x² + C
= 2x⁴ - 4x³ + 3x² + C

jawaban yang B,integral biasa
8/4 x^4-12/3x^3+6/2x^2+c

2x^4-4x^3+3x^2+c