tolong bantu saya hri senin sudh dikumpulkan

[tex] \frac{y - y1}{y2 - y1} = \frac{x - x1}{x2 - x1} \\ \frac{y - ( - 6)}{3 - ( - 6)} = \frac{x - ( - 3)}{2 - ( - 3)} \\ \frac{y + 6}{3 + 6} = \frac{x + 3}{2 + 3} \\ \frac{y + 6}{9} = \frac{x + 3}{5} [/tex]
5 × (y + 6) = 9 × (x + 3)
5y + 30 = 9x + 27
5y = 9x + 27 - 30
5y = 9x - 3
[tex]y = \frac{9}{5} x - \frac{3}{5} [/tex]

berpotongan dengan sumbu y berarti x = 0

[tex]y = \frac{9}{5} x - \frac{3}{5} \\ y = \frac{9}{5} \times 0 - \frac{3}{5} \\ y = - \frac{3}{5} [/tex]
koordinat = (0, -3/5)