penyelesaian dari sistem persamaan 3x+2y-4=0 dan x-3y-5=0

x-3y-5 = 0
x = 3y + 5

substitusikan x = 3y+5 ke persamaan 3x+2y-4 = 0

3x+2y-4 = 0
3 (3y+5) + 2y - 4 =0
6y +15 +2y -4 = 0
8y + 11 = 0
8y = -11
y = -11/8
y = -1 3/8

x = 3y + 5
x = 3 (-11/8) + 5
x = -33/8 + 5
   = 8 (-33/8 +5 )
   = -33 + 40
x = 7

sorry kl slh hehe