Itu gimana ya kak?kalau bisa sekalian penjelasannya

[tex] ^{7} log2 = a \\ ^{2} log3 = b \\ \\ ^{98} log6 \\ = \frac{^{2} log6}{ ^{2}log98 } \\ = \frac{ ^{2} log2.3}{ ^{2}log2.49 } \\ = \frac{ ^{2}log2 + ^{2}log3 }{ ^{2}log2 + ^{2}log {7}^{2} } \\ = \frac{1 + ^{2}log3 }{1 + 2. ^{2}log7 } \\ = \frac{1 + b}{1 + 2. \frac{1}{^{7}log2} } \\ = \frac{1 + b}{1 + 2.\frac{1}{a} } \\ = \frac{1 + b}{1 + \frac{2}{a} } \\ = \frac{1 + b}{ \frac{a + 2}{a} } \\ = 1 + b \times \frac{a}{a + 2} \\ = \frac{a(b + 1)}{a + 2} [/tex]
Jawaban B.