diketahui g(x)=x²-3 dengan daerah asal {-2,-1,0,1,2,3}.daerah hasil fungsi g adalah

g(x) = x^2 - 3
g(-2) = (-2)^2 - 3 = 1
g(-1) = (-1)^2 - 3 = -2
g(0) = (0)^2 - 3 = -3
g(1) = (1)^2 - 3 = -2
g(2) = (2)^2 - 3 = 1
g(3) = (3)^2 - 3 = 6

range = {1, -2, -3, 1, 6}

g(-2)= -2²-3 = 1
g(-1)= -1²-3 = -2
g(0)= 0²-3 = -3
g(1) = 1²-3 = -2
g(2)= 2²-3 = 1
g(3)= 3²-3 = 6

Jadi, daerah hasilnya = {1, -2, -3, -2, 1, 6}