tentukan penyelesaian (x,y,z) pada 2x+3y-z = 5; 4x-y+2z = 8 dan 3x-y+3z = 10

2x + 3y - z = 5
4x - y + 2z = 8
3x - y + 3z = 10
--> 4x - y + 2z = 8
3x - y + 3z = 10
----------------------- +
7x + 5z = 18

--> 2x + 3y - z = 5 ¦ x1 ¦ 2x + 3y - z = 5
4x - y + 2z = 8 ¦ x3 ¦ 12x -3y + 6z = 24
---------------------------- +
14x + 5z = 29

--> 7x + 5z = 18
14x + 5z = 29
--------------------- -
-7x = - 11
x = 11/7 (1,5)

--> 7x + 5z = 18 ¦ x2 ¦ 14x + 10z = 36
14x + 5z = 29 ¦ x1 ¦ 14x + 5z = 29
--------------------- -
5z = 7
z = 7/5 (1.4)

--> 2x + 3y - z = 5
2(1,5) + 3y - 1.4 = 5
3 + 3y - 1.4 = 5
3y = 5 + 1,4 - 3
3y = 3,4
y = 3,4/3 (1,1)

--> x = 11/7 (1,5)
--> y = 3,4/3 (1,1)
--> z = 7/5 (1,4)

*Maaf jika salah.