Matematika

Pertanyaan

nilai dari ^{2} log_{16} - 2 ^{2} log_{10} + ^{2} log_{25} - ^{2} log_{\frac{1}{4}}

1 Jawaban

  • [tex] ^{2} log16 - 2 ^{2} log10 + ^{2} log25 - ^{2} log \frac{1}{4} \\ ^{2} log16 - ^{2} log10 ^{2} + ^{2} log25 - ^{2} log \frac{1}{4} \\ = ^{2} log16 \div 100\times 25 \div \frac{1}{4} \\ = ^{2} log16 \div 100 \times 25 \times 4 \\ = ^{2} log16 \\ = 4[/tex]

    Semoga membantu :)

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