Diketahui suatu garis bergradien 5 melalui titik p(1,0) dan Q(a,5).Tentukan nilai a!

m =5
p(1,0)
x1 = 1 ; y1 = 0
Q(a,5)
x2 = a ; y2 =5

m PQ = y2-y1 / x2-x1
5 =5-0 / a-1
5(a-1) = 5
5a -5 = 5
5a = 10
a = 2