jika garis 3x + 4y + 2 = 0 berimpit dengan garis (a+1)x +(a+3)y +(a-1)=0, maka nilai a=.....

berhimpit = sama
3x + 4y + 2 = (a + 1)x + (a + 3)y + (a - 1)

a + 1 = 3
a = 3 - 1
a = 2

a + 3 = 4
a = 4 - 3
a = 1

a - 1 = 2
a = 2 + 1
a = 3