grafik fungsi kuadrat f(x)= ax2+bx+5 melalui titik a(-2,5) dan b(1,8). nilai (a2 + b2) =.....

Titik a : (-2,5)
ax^2+bx+5 = y
a(-2)^2+b(-2)+5 = 5
4a-2b = 5-5
4a-2b = 0

Titik b : (1,8)
a(1)^2+b(1)+5 = 8
a+b = 8-5
a+b = 3

4a-2b = 0 (kali 1)
a+b = 3 (kali 2)
----------------------
4a-2b = 0
2a+2b = 6
-----------------(ditambah)
6a = 6
a = 6/6
a = 1

a+b = 3
1+b = 3
b = 2

Nilai :
(a^2+b^2)
= ((1)^2+(2)^2)
= (1+4)
= 5

Maaf jika ada kesalahan :)