tolong jawab + caranya nomor 16

Diketahui:
○ n(A) = {(1, 1), (1, 2), (1, 3), (2, 1), (2, 2), (3, 1) → ada 6
○ n(S) = 6² = 36
○ Peluang: 6/36 = 1/6

Ditanya: Frekuensi Harapan n(A)?

Jawab:
Peluang x Banyak Pelemparan
= 1/6 x 36
= 1 x 6
→ 6 kali ( D )

dik : n(a) = (1,1)(1,2)(1,3)(2,1)(2,2)(3,1) = 6
n(s) = 36
lemparan ( n ) = 36 kali

dit : F(a) ??

jawab :

F(a) = n(a) / n(s) × n
= 6/36 × 36
= 6/1
= 6 kali

semoga membantu... .