Matematika

Pertanyaan

1. Akar–akar persamaan kuadrat 5x2 + x – 3 = 0 adalah x1 dan x2. Tentukan nilai dari
a. x1/x2 + x2/x1
b. 2x1/x2 + 2x2/x1
c. 1/x1 + 1/x2

2. Diketahui akar-akar persamaan kuadrat x2 – 2mx + 3m – 2 = 0 adalah x1 dan x2. Jika x12 – 2x1x2 + x22 = 48, tentukan nilai m!

pakai cara ya kalau bisa, terima kasih:))
kalo yg gtw pasti sebaiknya jgn d jwb dlu y ini aq mw bljr utk ujian. thankyou:))

2 Jawaban

  • 1) 5x² + x - 3 = 0
    a = 5 , b = 1 , c = - 3
    X1 + x2 = - b/a = - 1/5
    X1 • x2 = c/a = - 3/5

    a) X1/x2 + x2/X1

    = x1² + x2²
    ---------------
    X1 • x2

    = ( X1 + x2 )² - 2x1x2
    ------------------------------
    X1 • x2

    = ( - 1/5 )² - 2 ( - 3/5 )
    -------------------------------
    ( - 3/5 )

    = ( 1/25) + ( 6/5 )
    -------------------------
    ( - 3/5 )

    = ( 1/25 + 30/25 )
    --------------------------
    ( - 3/5 )

    = 31/25 ÷ - 3/5

    = 31/25 × - 5/3

    = - 31/15

    = - 2 1/15

    b) 2x1/x2 + 2x2/X1

    = 2x1² + 2x2²
    ---------------------
    X1 • x2

    = 2 ( x1² + x2² )
    -----------------------
    X1 • x2

    = 2 { ( X1 + x2 )² - 2x1x2 }
    --------------------------------------
    X1 • x2

    = 2 { ( - 1/5)² - 2(-3/5)}
    --------------------------------
    ( - 3/5 )

    = 2 { 1/25 + 6/5 }
    -------------------------
    - 3/5

    = 2 ( 1/25 + 30/25 )
    ------------------------------
    - 3/5

    = 62/25 ÷ -3/5

    = 62/25 × - 5/3

    = - 62/15

    = - 4 2/15


    c) 1/X1 + 1/x2

    = x2 + X1
    ---------------
    X1 • x2

    = - 1/5
    -------------
    - 3/5

    = - 1/5 ÷ - 3/5

    = - 1/5 × - 5/3

    = ⅓


    2) x² - 2mx + 3m - 2 = 0
    a = 1 , b = - 2m , c = 3m - 2

    x1² - 2x1x2 + x2² = 48
    ( X1 + x2 )² + 2x1x2 - 2x1x2 = 48
    (X1 + x2 )² = 48
    ( -b/a )² = 48
    ( 2m )² = 48
    4m² = 48
    m² = 48 : 4
    m = √12
    m = 2√3
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