Matematika

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titik yang terletak pada persamaan 4x+2y+2=0 adlh...

2 Jawaban

  • -Utk x = 0
    4x + 2y + 2 = 0
    4(0) + 2y + 2 = 0
    2y + 2 = 0
    2y = -2
    y = -1
    -Utk y = 0
    4x + 2y +2 =0
    4x + 2(0) + 2 = 0
    4x + 2 = 0
    4x = -2
    x = -1/2
    Titik yg bs sy dpt:
    (0 , -1) & (-1/2 , 0)
  • x = 0
    4x + 2y + 2 = 0
    4(0) + 2y + 2 = 0
    2y + 2 = 0
    2y = 0 - 2
    2y = - 2
    y = -2/2
    y = -1

    y = 0
    4x + 2(0) + 2 = 0
    4x + 2 = 0
    4x = 0 - 2
    4x = -2
    x = -2/4
    x = 1/-2

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