no 6 bagian c cara dan jawabanya ya!? Terimakasih:)

[tex]^{3} log ^{2} x - 3^{3} logx + 2 = 0 \\ ( ^{3} logx) ^{2} + 3 ^{3} logx + 2 = 0 \\ misal \: ^{3} logx = p \\ {p}^{2} + 3p + 2 = 0 \\ (p + 1)(p + 2) = 0 \\ \\ p = - 1 \\ ^{3} logx = - 1 \\ x = 3 ^{ - 1} \\ x = \frac{1}{3} \\ atau \\ p = - 2 \\ ^{3} logx = - 2 \\ x = 3^{ - 2} \\ x = \frac{1}{3 ^{2} } \\ x = \frac{1}{9} [/tex]
HP = {1/3, 1/9}

Semoga membantu :)