[tex] | {x}^{2} - 3x + 1| = 1[/tex] tentukan nilai x...

|x²-3x+1| = 1
✐ x² - 3x + 1 = 1
x² - 3x = 0
x(x-3) = 0
x = 0 , x = 3
✐ -(x²-3x+1) = 1
-x²+3x-1 = 1
-x²+3x-1-1 = 0
-x² + 3x - 2 = 0

Selesaikan dgn rumus ABC, sehingga
[tex]x = - \frac{ - 3 + 1}{2} \\ x = - \frac{ - 3 - 1}{2} \\ maka \\ x = 1 \: dan \: x = 2[/tex]

HP x = {0, 1, 2, 3}