simpangan baku dari 4,5,7,6,13,15,16,17,20,27 ?

jawab

xi = 4,5,6,7,13,15,16,17,20, 27
∑xi = 130
n = 10
X = 130/10 = 13

s² = { (4-13)² + (5-13)² + (6-13)² +(7-13)² +(13-13)² +(15-13)² +(16-13)² +(17-13)² +(20-13)² + (27-13)²} / 10

s²  = (81 + 64 + 49 + 36+ 0 + 4+ 9+16 + 49+196 )/10
s² = 504/10  = 50,4
simpangan baku s= √s² = 7,09