Suatu fungsi f(x)=ax+b f(1)=9 dan h(4)=-6, tentukan h(4)=

f(x)=ax+b
f(1)=a(1)+b
f= 1a+b
f=1ab

f(x)=ax+b

f(1) = a.1+b = 9
= a+b = 9

h(4)=a.4+b = -6
= 4a+b=-6

4a+b=-6 - a+b=9
3a=-15
a =-15/3
a = -5

a+b=9
-5+b=9
b=9+5
b=14

h(4)
a.4+b=-6
15.4+14=-6
60+14=-6
74=-6

semoga membantu!!!