Jika pH larutan 100ml NH4cl 0,01 m adalah (kb NH3 = 10^-5 (pangkat -5) , KW = 10^-14 (pangkat -14))

[tex]( {H}^{ + } ) = \sqrt{ka \times c} \\ = \sqrt{ \frac{ {10}^{ - 14} }{ {10}^{ -5} } \times {10 }^{ - 2} } \\ = \sqrt{ {10}^{ - 11} } \\ = \sqrt{10 \times {10}^{ - 12} } \\ = 3.1623 \times {10}^{ - 6} \\ \\ ph = - log( {H}^{ + } ) \\ = 6 - log(3.1623) \\ = 5.50[/tex]