Soal matriks invers. Tolong bantu yah

Materi Matriks

Sifat Matriks
[tex] PA = B \Leftrightarrow P = BA^{-1} [/tex]

A = [2 .1]
.......[4 3]

B = [-2... 1]
.......[14 10]

PA = B
PA . A^(-1) = B . A^(-1)
1P = B . A^(-1)
P = B . A^(-1)
P = [-2....1].1/2.[3...-1]
.......[14 10].......[-4..2]
P = [-2....1][3/2..-1/2]
.......[14.10][-2..........1]
P = [(-2)(3/2)+(1)(-2)....(-2)(-1/2)+(1)(1)]
.......[(14)(3/2)+(10)(-2)....(14)(-1/2)+(10)(1)]
P = [-3-2.........1+1]
.......[21-20..-7+10]
P = [-5..2]
.......[1.....3]

Jadi P = [-5..2]
................[1.....3]