pliss jawab pake cara nya ya

1) m = ( y2 - y1 ) / ( x2 - X1 )
m = ( -4 - 2 ) / ( -4 + 1 )
m = - 6 / - 3
m = 2

2) 2y - 3x = 4
2y = 3x + 4
m = 3/2

3) y - y1 = m ( x - X1 )
y - 6 = - 3 ( x - 0 )
y = - 3x + 6
y + 3x = 6

4) 2y + 3x = 0
2y = - 3x
m = - 3/2
gradien saling tegak lurus
m1 . m2 = - 1
- 3/2 . m2 = - 1
m2 = ⅔
pers garis
y - y1 = m ( x - X1 )
y + 5 = ⅔ ( x + 3 )
y = ⅔ x + 2 - 5
y = ⅔ x - 3 ( dikali 3)
3y = 2x - 9
3y - 2x = 9

5) 8a² - 2a - 15 = 0
( 4a + 5 )( 2a - 3 ) = 0
4a = - 5 atau 2a = 3
a = - 5/4 atau a = 3/2
hp = { - 5/4 , 3/2 }

Jawabannya:
1. m=(-4-2)/(-4+1)
m= -6/-3
m= 2

2. 2y-3x=4
2y= 3x+4
m= 3/2

3. y-6= -3(x-0)
y= -3x+6
y+3x=6

4. 2y+3x=0
2y= -3x
m= 3/2
Tegak Lurus
m1.m2 = -1
-3/2.m2= -1
m2= -3/2/ -1
m2= 2/3

Pers Garisnya:
y-y1=m(x-x1)
y+5=2/3(x+3)
y= 2/3x+2-5
y= 2/3x-3. |×3|
3y=2x-9
3y-2x=9

5. 8a²-2a-15=0
(4a+5)(2a-3)=0
4a= -5 atau 2a= 3
a= -5/4 atau a= 3/2

HP= { -5/4, 3/2 }

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